Hive 报错SemanticException Error in parsing

以下sql执行时报错SemanticException Error in parsing

select clr.id,clr.customer_id,clr,contract_code,clr.core_asset_request_id,wa.user_id
--,u.name
from zcfw_sda.sda03_asset_info clr
left join qz_sda.sda03_withdraw w
on clr.contract_code = w.contract_no
and w.etl_tx_dt = ${v_dt2num}
left join qz_sda.sda03_withdraw_apply wa
on w.withdraw_apply_no = wa.withdraw_apply_no
and wa.etl_tx_dt = ${v_dt2num}
--left join qz_sda.sda03_user u
--on wa.user_id = u.id
--and u.etl_tx_dt = ${v_dt2num}
where clr.etl_tx_dt =20191103
and to_date(clr.loan_time) =‘2019-11-03‘
and clr.contract_code=‘2191103751278446‘

报错信息:

Hive 报错SemanticException Error in parsing

英文翻译过来是语义解析错误,

检查了下是在hql中别名后面的.不小心写成了,导致报错。

正确写法:

select clr.id,clr.customer_id,clr.contract_code,clr.core_asset_request_id,wa.user_id
--,u.name
from zcfw_sda.sda03_asset_info clr
left join qz_sda.sda03_withdraw w
on clr.contract_code = w.contract_no
and w.etl_tx_dt = ${v_dt2num}
left join qz_sda.sda03_withdraw_apply wa
on w.withdraw_apply_no = wa.withdraw_apply_no
and wa.etl_tx_dt = ${v_dt2num}
--left join qz_sda.sda03_user u
--on wa.user_id = u.id
--and u.etl_tx_dt = ${v_dt2num}
where clr.etl_tx_dt =20191103
and to_date(clr.loan_time) =‘2019-11-03‘
and clr.contract_code=‘2191103751278446‘

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