我的python日记---DAY1
之前学习了Alex的python教程Alex的教学真的非常棒，也很幽默。嘿嘿。希望自己可以坚持下去。
把之前学的基础知识整理回顾了一下。希望自己可以在学习python的路上越走越远，大家互勉奥。
第一周 复习总结 1 初始游戏代码number_of_kids =8guess_number=int(input("guess_number_of_kids:"))if guess_number==number_of_kids: print("You got it!")elif guess_number>number_of_kids: print("think smaller...")else: print("think bigger...")
猜三次 猜三次没猜中 就退出 则要使用到循环
（ while初相识 代码1： count = 0while True: print("count:",count) count = count +1 #count +=1 无线循环-----运用到上面的猜数字游戏 ）
想要在某个地方停止 要如何设置?
简单举例whilecount = 0while True: print("count:",count) count = count *2 #count*=2 if count == 1000: break 问： 该如何加？使初始游戏 能循环猜测？ 改进2
number_of_kids =8
while True: guess_number=int(input("guess_number_of_kids:"))
if guess_number==number_of_kids: print("You got it!") elif guess_number>number_of_kids: print("think smaller...") else: print("think bigger...")
问题： 为什么while true 要放在这个位置？ 答：while true 代表无限循环，不中断。若while true 放在下面一行的下面的话， 会无法循环下一个input，即会中断游戏。
运行结果：可无限次输入数字猜测 无限循环 缺点：当输入正确答案时仍然继续猜测，没有结束。 问：改进如何在猜对的时候 直接结束程序
改进3：
number_of_kids =8
while True: guess_number=int(input("guess_number_of_kids:"))
if guess_number==number_of_kids: print("You got it!") break elif guess_number>number_of_kids: print("think smaller...") else: print("think bigger...")
break的添加可以使得在猜对数字的时候 结束游戏。但若猜不对如何是之在 指定次数内结束游戏？
改进4：
number_of_kids =8
count = 0
while True:
if count ==3: break guess_number=int(input("guess_number_of_kids:"))
if guess_number==number_of_kids: print("You got it!") break elif guess_number>number_of_kids: print("think smaller...") else: print("think bigger...")
加了 if count ==3:break 后，还是没有在第三次猜测的时候成功。原因： 没有加计数！
number_of_kids =8
count = 0
while True:
if count ==3: break guess_number=int(input("guess_number_of_kids:"))
if guess_number==number_of_kids: print("You got it!") break elif guess_number>number_of_kids: print("think smaller...") else: print("think bigger...")
count+=1 非常棒！ 是否可以优化？
问：有什么可以代替 if count ==3: break 以及计数？
number_of_kids =8
count = 0
是否还可以优化？
有什么可以代替 if count ==3: break while True:
if count <3: guess_number=int(input("guess_number_of_kids:"))
if guess_number==number_of_kids: print("You got it!") break elif guess_number>number_of_kids: print("think smaller...") else: print("think bigger...") count+=1 print("you have tried too many times..fuck off")
只有在第三次还没有猜对的情况下进行fuckoff 进行以下修改：
number_of_kids =8
count = 0
while count <3: guess_number=int(input("guess_number_of_kids:"))
if guess_number==number_of_kids: print("You got it!") break elif guess_number>number_of_kids: print("think smaller...") else: print("think bigger...")
count+=1
if count ==3: print("you have tried too many times..fuck off") 改进：高级一点哈哈哈哈 number_of_kids =8
count = 0
while count <3: guess_number=int(input("guess_number_of_kids:"))
if guess_number==number_of_kids: print("You got it!") break elif guess_number>number_of_kids: print("think smaller...") else: print("think bigger...")
count+=1
else: print("you have tried too many times..fuck off") 小傻作业： 4/9 周日
如何变动代码，使得第三次出来的时候 只显示数字，不显示fuckoff，等第四次输入的时候，不提示大小，反而直接输出fuckoff？ 首先，理清上一段代码的思路：count从0开始运行 进入while循环，但凡在小于3的范围内 只要猜对 就break。没猜对 就出现smaller or bigger。当count+=1等于2时，即进入第三次循环，再一次猜错时 出现bigger or smaller 后 走下一个程序，即count+=1等于3，进入else运行，后面紧跟fuckoff。
作业改动思路：要使的第三次出来的时候 只显示数字 和小了大了提示，不显示fuckoff，则说明当count+=1等于3时，不直接走fuckoff的程序，则说明fuckoff的设置不能出现在前面while count <3 的子程序中，而是应该并列程序，当count=3时，继续出现猜数字的界面，后不管猜错猜对都fuckoff，并且结束。
number_of_kids =8
count = 0
while True:
if count <3: guess_number =int(input("guess_number_of_kids:"))
if guess_number==number_of_kids: print("You got it!") break elif guess_number>number_of_kids: print("think smaller...") else: print("think bigger...")
count+=1
if count ==3: guess_number =int(input("guess_number_of_kids:")) print("you have tried too many times..fuck off") break
while优化课
如何用for来代替 while
number_of_kids =8
count = 0
while count <3: #for i in range（3） guess_number=int(input("guess_number_of_kids:"))
if guess_number==number_of_kids: print("You got it!") break elif guess_number>number_of_kids: print("think smaller...") else: print("think bigger...")
count+=1
else: print("you have tried too many times..fuck off")
改成：
number_of_kids =8
count = 0
#for i in range（3） guess_number=int(input("guess_number_of_kids:"))
if guess_number==number_of_kids: print("You got it!") break elif guess_number>number_of_kids: print("think smaller...") else: print("think bigger...")
count+=1
else: print("you have tried too many times..fuck off")
最基本的for循环。
for i in range(0,10,1): #1是默认值，可以不写，不写即代表1. print("loop",i)
for i in range(0,10,2): print("loop",i)运行结果：=== RESTART: C:/Users/dell/AppData/Local/Programs/Python/Python35-32/12.py ===loop 0loop 2loop 4loop 6loop 8>>>
for i in range(0,10,3): print("loop",i)运行结果：=== RESTART: C:/Users/dell/AppData/Local/Programs/Python/Python35-32/12.py ====== RESTART: C:/Users/dell/AppData/Local/Programs/Python/Python35-32/12.py ===loop 0loop 3loop 6loop 9>>>
再次优化猜数字游戏：猜三次就退出貌似很决绝，是不是可以根据个性化需求设置提示？加：问还要不要玩？
number_of_kids=8
count=0
while count <3: guess_number = int(input("guess_number_of_kids:")) if guess_number == number_of_kids: print("yep,you got it!") break elif guess_number> number_of_kids: print("think smaller...") else: print("think bigger...")
count+=1 if count==3: countine_confirm = input("do you want keeping guessing...?") if countine_confirm !="n": 若是按下n则表示退出游戏 count =0 当按下回车键后表明还想玩，则程序继续执行。
task： 单独打出这段代码，理清思路。
新知识点： continue
for i in range(0,10): if i<3: print("loop",i) else: continue print("hehe"..) 执行结果 ：=== RESTART: C:/Users/dell/AppData/Local/Programs/Python/Python35-32/4.py ===loop 0hehe...loop 1hehe...loop 2hehe...
后来加断点？？？啥意思？for i in range(0,10): if i<3: print("loop",i) else: continue(作用是跳出本次循环，进入下一次循环） print("hehe"..)问： 同样代码 却没有hehe？
新知识点：双循环
for i in range(10): print("________",i) for j in range(10): print(j) 执行结果：=== RESTART: C:/Users/dell/AppData/Local/Programs/Python/Python35-32/4.py ===________ 0