Shell简单管理iptables脚本
由于新来的同事对脚本不是很熟悉，为了方便管理服务器上的iptables，于是决定写上个简单的脚本，这样对不是很熟悉脚本的同事都能简单管理。以下的脚本只是用一个循环就搞定了！如果哪里写的不好，或者有更好的想法或者写法，麻烦联系我！
[root@localhost ~]# cat iptables.sh
#!/bin/bash
while [ "1" == "1" ]
do
clear
echo "----------------------menu----------------------"
echo "(1) service iptables restart"
echo "(2) iptables add"
echo "(3) iptables delete"
echo "(4) iptables stop"
echo "(5) iptables save(输完ACL后要记得保存和查看)"
echo "(6) iptables status"
echo "(7) iptables ACL list"
echo "(0) exit"
echo "-------------------------------------------------"
echo -n "enter you chose[0-7]:"
read num
if [ ${num} -lt 0 -o ${num} -gt 7 ]
then
echo "this is not between 0-7"
else
if [ "${num}" == "1" ]
then
service iptables restart&
else
if [ "${num}" == "2" ]
#######################################################
then
while [ "1" == "1" ]
do
clear
echo "----------------------add ACL----------------------"
echo "(1) 针对源IP放行添加"
echo "(2) 针对服务器端口放行添加"
echo "(3) 针对有端口和服务的ACL添加（这里要参数IP和端口 例如 0/0 80）"
echo "(4) 自定义添加"
echo "(5) 退回上一级"
echo "-------------------------------------------------"
echo -n "enter you chose[0-4]:"
read aclnum
if [ "${aclnum}" == "1" ]
then
read ip
iptables -A INPUT -s ${ip} -p tcp --dport 22 -j ACCEPT
service iptables save
elif [ "${aclnum}" == "2" ]
then
rad ip
iptables -A INPUT -p tcp --dport ${IP} -j ACCEPT
service iptables save
elif [ "${aclnum}" == "3" ]
then
read ip port
iptables -A INPUT -p tcp -s ${ip} --dport ${port} -j ACCEPT
service iptables save
elif [ "${aclnum}" == "4" ]
then
read addacl
`${addacl}`
service iptables save
else
break
fi
echo -n "是否想继续添加: [y/n]:"
read contine
if [ "${contine}" == "n" -o "${contine}" == "N" ]
then
break
fi
done
#######################################################
else
if [ "${num}" == "3" ]
then
while [ "1" == "1" ]
do
clear
echo "---------------------delete ACL----------------------"
echo "(1) 针对源ip删除"
echo "(2) 针对端口删除"
echo "(3) 针对有端口和服务的ACL删除"
echo "(4) 自定义删除"
echo "(5) 退回上一级"
echo "-------------------------------------------------"
echo -n "enter you chose[0-5]:"
read aclnum
if [ "${aclnum}" == "1" ]
then
read ip
iptables -D INPUT -s ${ip} -p tcp --dport 22 -j ACCEPT
service iptables save
elif [ "${aclnum}" == "2" ]
then
read port
iptables -D INPUT -p tcp --dport ${port} -j ACCEPT
service iptables save
elif [ "${aclnum}" == "3" ]
then
read ip port
iptables -D INPUT -p tcp -s ${ip} --dport ${port} -j ACCEPT
service iptables save
elif [ "${aclnum}" == "4" ]
then
read deleteacl
`${deleteacl}`
service iptables save
else
break
fi
echo -n "是否想继续添加: [y/n]:"
read contine
if [ "${contine}" == "n" -o "${contine}" == "N" ]
then
break
fi
done
###################################################################
else
if [ "${num}" == "4" ]
then
echo -e "`service iptables stop&` "
else
if [ "${num}" == "5" ]
then
echo -e "`service iptables save&`"
else
if [ "${num}" == "6" ]
then
echo -e "`service iptables status&`"
else
if [ "${num}" == "7" ]
then
while [ "1" == "1" ]
do
clear
echo "---------------------list ACL----------------------"
echo "(1) 查看当前正在使用的规则集"
echo "(2) 查看每个策略或每条规则、每条链的简单流量统计"
echo "(3) 查看NAT表"
echo "(4) 自定义查看"
echo "(5) 退回上一级"
echo "-------------------------------------------------"
echo -n "enter you chose[0-5]:"
read aclnum
if [ "${aclnum}" == "1" ]
then
iptables -L
elif [ "${aclnum}" == "2" ]
then
iptables -L -n -v
elif [ "${aclnum}" == "3" ]
then
iptables -L -t nat
elif [ "${aclnum}" == "4" ]
then
read listacl
`${listacl}`
else
break
fi
echo -n "是否想继续添加: [y/n]:"
read contine
if [ "${contine}" == "n" -o "${contine}" == "N" ]
then
break
fi
done
################################################
else
exit
fi
fi
fi
fi
fi
fi
fi
fi
echo -n "Do you contine [y/n]:"
read contine
if [ "${contine}" == "n" -o "${contine}" == "N" ]
then
exit
fi
done