堆排序的python实现

import math def build_heap(arr): # 创建堆 for i in range(1, len(arr)): s = i p = math.ceil(s / 2) - 1 while p >= 0: if arr[s] > arr[p]: arr[s], arr[p] = arr[p], arr[s] else: break s = p p = math.ceil(s / 2) - 1 return arr def sort(arr): # 创建排序列表 result_list = [] while arr: arr = build_heap(arr) result_list.append(arr.pop(0)) return result_list l = [5, 2, 7, 8, 6, 1, 4, 9, 10, 1, 2, 3, 4, 100] print(sort(l)) ?

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